
William W. answered 09/14/21
Experienced Tutor and Retired Engineer
distance = speed multiplied by time or, in Physics "lingo", x = vt (x = distance, v = velocity, t = time)
x = (9 m/s)(58s) = 522 m
If you wanted to use the proper number of significant figures, there is only 1 sig fig in 9 m/s so the answer should just have 1 sig fig as well meaning we should round the answer to 500 m