Physics Review for test

Question

Two buildings are separated by a distance d. An object is thrown horizontally at a speed of 15 m/s from the first building to the second. The object strikes the second building 20 m below the point it was thrown. The distance between the buildings is

Answer 1

You'll need to split the motion into its horizontal and vertical components.

Vertical motion: If you ignore air resistance, the object will fall at a rate determined by g (9.8 m/s/s). You can use the distance formula to figure out how long it took to fall 20m.

s = s₀ + v₀t + ½at²

^{In this case, s0 and v0 are zero, so the equation simplifies to:}

s = ½at²

^{Solve for t.}

^{Horizontal motion: ignoring air resistance, the distance the object travels in t seconds is determined by:}

^s=vt

^{You know v and t, solve for s.}