
William W. answered 09/05/21
Experienced Tutor and Retired Engineer
The constant acceleration equations will work over intervals where the acceleration is constant but when it is not constant you will need to use a Calculus approach.
In your example, just because you want the function to be constant between 1 & 2 doesn't mean it is. Here is a possible graph:
It truly is possible that the acceleration is constant between 1 & 2 but it is more reasonable that the acceleration changes gradually over the interval. Assuming the velocity is the blue curve, there is at least one point between 1 & 2 where the acceleration equals the slope of the straight line between 1 & 2.(that is the mean value theorem). But notice that the tangent line varies over that interval. If you assume that the acceleration is constant, your calculations will be close but will have some built-in error. The smaller the interval, the less the built-in error will be.

William W.
You’re trying too hard to force a situation into constant acceleration. If an acceleration is close to being constant and you then use the equations associated with constant acceleration, then your answers will be close. The closer the acceleration gets to being constant, the closer your answers will be to reality. If you can define acceleration as a function, then you can define velocity or position exactly. The question all boils down to “how close do you want your answers to be to reality?”09/08/21
Rahul A.
ok thanks, but in constant acceleration how can we say that an acceleration is constant at a particular interval,like it is constant for intervals 1-2 2-3 3-4 and so on... but what about if we take a particular interval, for instance 1-2 and chop it down into 4 or say 5 intervals,then is it constant for that intervals too? so how can we use the formula v1+v2/2 there if we don't know whether it is constant in between the interval too. and also why can't we say then in non uniform motion, that for a particular interval the acceleration was constant. coz acceleration is given by v2 st an instant minus v1 at an instant. we ignore the fact what happens in between a interval in constant acceleration example too. right?09/08/21