Ben G. answered 09/02/21
Experienced Instructor and Tutor with Masters from U of Michigan
This becomes a trigonometry problem. If you have a right triangle with two sides known, then the third side can be found with the Pythagorean relationship. (a^2 + b^2 = c^2). In this case c, the hypotenuse, is the length of vector R. Thus, the magnitude is sqrt( 18^2 + 25^2 ) = 30.8 m.
To find the angle, you want to think back to SOH-CAH-TOA (acronym for Sin θ = opposite / hypotenuse, cos θ = adjacent / hypotenuse, and tan θ = opposite / adjacent). Here tangent would be the best choice because it doesn't depend on your answer to part 1. Therefore, tan θ = 25 / 18 . This implies that θ = tan^-1( 25/18) = 45.3 degrees.

John D.
for part b it was cot^-1.ty for explanation09/02/21