Motion Equations for Constant Acceleration in One Dimension

Question

A powerful motorcycle can accelerate from rest to 29.8 m/s (67 mi/h) in only 1.90 s. (For each answer, enter a number.)

(a)

What is its average acceleration in m/s²?

 m/s²

(b)

How far (in m) does it travel in that time?

 m

Answer 1

a) The average acceleration is obtained by dividing the final velocity minus the initial velocity by the time.

In this case the calculation is (29.8 - 0) m /s / 1.90 s = 15.7 m / s².

b) The distance traveled is the average velocity x time = (29.8+ 0) /2 x 1.90 = 28.3 m.