Sidney P. answered 08/26/21
Minored in physics in college, 2 years of recent teaching experience
1a. Doppler shift v/c ≈ z = Δλ/λo = (589 - 725)/725 = -0.1876 [I keep 1 more figure than number of sig figs to minimize roundoff error]. v ≈ cz = -5.624 x 107 m/s (1 mph /0.4470 m/s) = -1.26 x 108 mph towards the light.
[Probably you're not doing the relativistic correction, but just in case: z = [(c+v)/(c-v)]1/2 - 1 and after algebra, v/c = [1 - (1+z)2] / [1 + (1+z)2] = (1 - .6600) / (1 + .6600) = 0.2048 and v = (-) 1.37 x 108 mph.]
1b. z = -0.1876 = (x - 589)/589, x - 589 = -110, x = 479 nm = Blue.
2a. z = 0.00619 = (λ - λo) / λo, 0.00619 λo = 680.9 - λo, (1.00619) λo = 680.9, λo = 676.7 nm.
2b. Relative v/c = (Δλ = -4.20)/680.9 = -0.006168, v = -1.849 x 106 m/s = -4.14 x 106 mph.