
Edward F. answered 08/21/21
Always Happy to Help
- L=1/2m(dx/dt)^2
- The Euler-Lagrange equations states that d/dt(dL/(dx/dt))-dL/dx=0. dL/(dx/dt) gives us m(dx/dt), and d/dt(dL/(dx/dt)) gives us m(d^2 x / dt^2), i.e., ma (mass times acceleration), and since there is no potential, V(x) = 0, this implies that dL/dx = 0, so we obtain newton's law ma=0.
- Either the particle has no mass, or no acceleration, or neither. Momentum is conserved.
- ma = 0 -> v = C -> x = Ct+D (C is a constant, and D is a constant). x = 0 at t=0 implies 0=0+D -> D=0 -> x = Ct -> v=C. So if v=v0 at t=0, v always equals v0 -> C=v0, so our equation of motion is x=v0*t. This is constant motion.