Two capacitors, C₁ and C₂, are connected in parallel. C₁ = 5.00 x 10-5 F and the equivalent capacitance of the pair is 7.50 x 10-5 F. What is the capacitance of C2?

Answer 1

Hello Tamia,

Ceq in Parallel = C1 + C2 =7.5*10^-5 F

C1 = 7.5*10^-5 F

C2 = 7.5* 10 ^-5 - 5.0 *10^-5 = 2.5* 10^-5 F

C2 = 2.5*10^-5 F

Answer 2

C = C₁ + C₂; C₂ = C - C₁ = 7.5·10^-5F - 5.0·10^-5F = 2.5·10^-5 F