If he leaves class​ late, there is a 46​% chance that he will miss his train. What is the probability that he gets out of class late and misses the​ train?

Question

A student figures that he has a 51​% chance of being let out of class late. If he leaves class​ late, there is a 46​% chance that he will miss his train. What is the probability that he gets out of class late and misses the​ train?

The probability is _____.

​(Round to three decimal places as​ needed.)

Answer 1

Event A = get out of class late

Event B = miss train

P(B|A) = P(A and B)/P(A)

P(B|A) is 0.46

P(A) = 0.51 so

0.46 = P(A and B) /0.51

0.46*0.51 = P(A and B)

0.2346 = P(A and B)