Hi Leslie,
I'll try and get you started but it is difficult to do without a graphic tool.
The upper boundary is the parabola y=2x2
Part of the lower boundary is the tangent line to the parabola at (2,8) so our first task is to find the equation for this line and then find out where this line intersects the x axis.
The slope of this line is dy/dx @x=2, dy/dx =4x and at x=2 is equal to 8. So the tangent line is (y-8)=8(x-2) and rearranging gives y=8x-8. This line intersect the x axis at x=1 which is one of the limits of our integral.
The area is A=∫012x2dx +∫12(2x2-8x+8)dx I'll leave the integration to you.
Hope this helps
Jim
Leslie C.
03/07/15