Determine which of the given points are on the graph of the equation?

Question

Which of these points are on the graph of the​ equation? Select all that apply.

Equation y = x^4 - square root of -x

Points: (0,3), (1,0), (-1,-2)

Answer 1

(0,3), (1,0) (-1,-2)

x^4 - sqr(-x)

to avoid an imaginary number, x has to be negative

otherwise -x will be negative and the square root of a negative number is imaginary.

only possibility is (-1,-2) but (-1)^4- sqr(--1) = 1-1=0 not -2

(0)^4 -sqr0 + 0-0=0 not 3

(1)^4 - sqr(-1) = 1-i which is not 0

(1,0) would be the correct answer if the problem had been x^4 -sqrx maybe there's a typo in the problem?

Answer 2

If y = x⁴ - √(-x) and x = 0, from the point (0, 3), then y = 0⁴ - √(-0) = 0 so the point (0, 3) is NOT on the curve.

If y = x⁴ - √(-x) and x = 1, from the point (1, 0), then y = 1⁴ - √(-1) = "1 - i" so the point (1, 0) is NOT on the curve.

If y = x⁴ - √(-x) and x = -1, from the point (-1, -2), then y = (-1)⁴ - √(-(-1)) = 0 so the point (-1, -2) is NOT on the curve.

Answer 3

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