T2(x) = g(0) + g'(0) x + (1/2)g''(0) x2 = 13 −11x +(1/2) 6 x2 = 13 −11x +3 x2
T2(x) = 13 −11x +3 x2
T3(x) = g(0) + g'(0) x + (1/2)g''(0) x2 + (1/6) g"' (0) x3
T3(x) = 13 −11x +3 x2 + (1/6) g"' (0) x3 = 13 −11x +3 x2 +(1/6) 9 x3 = 13 −11x +3 x2 +(3/2) x3
T3(x) = 13 −11x +3 x2 +(3/2) x3
T2(0.2) = 10.92
T3(0.2) = 10.932

Adam B.
08/04/21
Lily E.
Thank you so much for explaining this in such detail, you helped so much! I appreciate it!08/04/21