Dr Gulshan S. answered 08/12/21
Tutor
4.9
(52)
Physics Teaching is my EXPERTISE with assured improvement
PE = K q1q2/ r12. +Kq2q3/ r13 + K q1q3/r13
K = 9*10^9
r12= 1.15 r23 =2.88. r13 = 1.15 + 2.88
plug in all q values with signs and get answer in Joule