Tom K. answered 07/18/21
Knowledgeable and Friendly Math and Statistics Tutor
The standard process for this is to state that, as this is an alternating series, the error is less than the absolute value of the next term.
If 2/n^.8 < .01, .01n^.8 > 2, or n^.8 > 200, or (n^.8)^1.25 > 200^1.25, or n > 200^1.25 > 752.12
The 753rd term will have absolute value less than .01, so n = 752 is sufficient.
(Further analysis showed that approximately 316 is sufficient; you can actually look for the first term with absolute value less than twice the error at some point given the smooth nature of the slow decline; 100^1.25 = 316.2278.)

Adam B.
07/18/21