Inactive Tutor answered 07/18/21
The standard process for this is to state that, as this is an alternating series, the error is less than the absolute value of the next term.
If 2/n^.8 < .01, .01n^.8 > 2, or n^.8 > 200, or (n^.8)^1.25 > 200^1.25, or n > 200^1.25 > 752.12
The 753rd term will have absolute value less than .01, so n = 752 is sufficient.
(Further analysis showed that approximately 316 is sufficient; you can actually look for the first term with absolute value less than twice the error at some point given the smooth nature of the slow decline; 100^1.25 = 316.2278.)
Adam B.
07/18/21