Solve 3 sin ( 2 θ ) − 3 sin ( θ ) = 0 3 sin ( 2 θ ) - 3 sin ( θ ) = 0 for all solutions 0 ≤ θ < 2 π 0 ≤ θ < 2 π θ θ =

Answer 1

 3 sin ( 2 θ ) − 3 sin ( θ ) = 0

same as

6sinθcosθ-3sinθ=0

sinθ=0 will solve, sinθ=0 when θ=0 and θ=π

within interval given

assume θ not 0 or π, then dividing by sinθ allowed

now have to solve 6cosθ-3=0

cosθ=1/2 when θ=π/3 and θ=5π/3

within the interval given