Jason D. answered 07/12/21
Master in Mech. Eng. with 30+ Years of Teaching Experience
a. Ek= 1/2 mV2= 1/2 x 56 x 162= 7,168 J
b. Ep= mgh= 56 x 9.81 x 34 = 18,678.24 J
c. Et= 7,168 + 18,678.24= 25,846.24 J
d. Because no energy is lost or gained between the top of the hill and her initial
arrival at the end of the run, then the total mechanical energy at the end of the run would be equal to the total mechanical energy at the top of the hill or any place across the crest and at the bottom of the crest. Thus, Et= 25,846.24 J
e. Et=1/2 mVb2
25,846.24= 1/2 x 56 x Vb2
Vb=30.38 m/s