q1 = -4.60 x 10-5 C, q2 +3.10 x 10-6 C, and 93 = -8.30 x 10-5 C. Find the y-component of the net force on q2. Include the correct + or - sign to indicate direction.

Question

Q1 is connected to Q2 (left to right) with a distance of 0.350 meters. Q2 is connected Q3 (up-down) with a distance of 0.155 meters.

Answer 1

Since q1 and q2 are aligned with the x-axis (left-right) then there is no associated force component in the y-direction associated with their charges. So, use Coulombs law:

where k = 8.988 × 10⁹ N⋅m²⋅C⁻² so:

F = (8.988 × 10⁹)(3.10 x 10^-6)(8.30 x 10^-5)/(0.155²) = 96.3 N and since q₂ and q₃ are opposite signs, the force is directed from q2 toward q3