"Q1= +6.60 x 10-6 C, Q2= +3.10 x 10-6 C, and Q3= +5.30 x 10-6 C. What is the magnitude and direction of the net force on charge q2? Q1-Q2=0.350 and q2-q3=0.155?"

Answer 1

First, establish the direction of the forces on q2: F₁₂ is to the right. F₃₂ is to the left. The total force on 2 will be F₁₂ - F₃₂ to the right (if it turns out to be negative, the net force is to the left.

F_i2 = k_eq_iq₂/d² where i is 1 or 3. In order to use k - 8.99 x 10⁹ the distances must be in meters.

Good luck!

Answer 2

Hi Tamia,

Can you please show me the diagram or location of charges to answer this question ?