Sidney P. answered 06/18/21
Minored in physics in college, 2 years of recent teaching experience
The magnitudes of the gravitational forces between Earth and the bag are equal, |Fg| = |ME aE| = |mb g|, so aE = (7.33 kg) (9.81 m/s2) / (5.98 x 1024 kg) = +1.202 x 10-23 m/s2.
Δy = vo t + 1/2 a t2, -4.57 = 0 - (9.81/2) t2, t2 = 0.9317 and t = 0.9652 s.
vE = vo + aE t = 0 + 1.16 x 10-23 m/s.