Provide an exact expression, not a decimal approximation.

Question

Let f(x) = 6x ^ 2 + 2 .Evaluate f(1 + sqrt(5)).

f(1 + sqrt(5)) =

Answer 1

f(1+sqrt{5})=6(1+sqrt{5})^2+2

=6(1+2sqrt{5}+5)+2

=6(6+2sqrt{5})+2

=36+12sqrt{5}+2

=38+12sqrt{5}

Answer 2

It is a little weird to look at this problem!!

you are used to using x a the thing you are trying to solve or figure out cuz the graph the f(x) is a function with respect to x literaly!

So just copy paste the weird looking complex number into the given function f(x) = 6(x)^2+2

so f(1+sqrt(5))= 6((1+sqrt(5))^2)+ 2

=6(1+2(sqrt(5))+5) + 2

= 36+12(sqrt(5))+2

= 38 + 12(sqrt(5)) = answer !!

Answer 3

f( 1+ sqrt(5) ) = 6( 1+sqrt(5) )^2+2 = 6( 1 + 2sqrt(5) +5) +2 = 36+12sqrt(5)+2 = 38+12sqrt(5).