Sidney P. answered 06/16/21
Astronomy, Physics, Chemistry, and Math Tutor
I get answer [a], because the reciprocal 1/y = - 1/[3(x + 3)] has vertical asymptote at x = -3 and horizontal asymptote at y = 0 (when x approaches infinity).
Parth B.
asked 06/16/21a) d: {x|x∈R, x ≠ -3} r: {y|y∈R, y ≠ 0}
b) d: {x|x∈R, x ≠ 0} r: {y|y∈R, y ≠ 3}
c) d: {x|x∈R, x ≠ 3} r: {y|y∈R, y ≠ -3}
d) d: {x|x∈R, x ≠ 9} r: {y|y∈R, y ≠ 0}
Sidney P. answered 06/16/21
Astronomy, Physics, Chemistry, and Math Tutor
I get answer [a], because the reciprocal 1/y = - 1/[3(x + 3)] has vertical asymptote at x = -3 and horizontal asymptote at y = 0 (when x approaches infinity).
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