Mimi G.
asked • 06/15/21The velocity-time graph
The velocity-time graph of part of a cyclist's trip consists of a straight line between v = 23.0 m/s at t = 14.0 s and v = 0 at t = 24.0 s. What distance was covered during this portion of the trip?
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1 Expert Answer
Anthony T. answered • 06/15/21
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The fact that the graph is a straight line sloping downward indicates that the velocity is decreasing at a constant deceleration. In cases of constant acceleration or deceleration, the average velocity is the sum of the final velocity and the initial velocity divided by 2.
In this case the distance travelled during the 10 second interval is D = (23.0 + 0) /2 m/s x 10 sec. = 115 meters
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Rajai A.
hi you need to find the area under the graph between t=14.0s and t=24.0s . the shape is triangle A= ( base / 2) × hight . the area equals the distance. base =( (24 -14) hight = 2306/15/21