A circle has center (6, 2) and radius 9. Find all values of such that (x, - 1) is a point on the circle.

Question

A circle has center (6, 2) and radius 9. Find all values of such that (x, - 1) is a point on the circle.

Answer 1

Answer 2

Equation of the circle:

(x - 6)^2 + (y - 2)^2 = 81

y is -1 so:

(x - 6)^2 + (-1 -2)^2 = 81

(x - 6)^2 + 9 = 81

(x - 6)^2 = 72

x - 6 = +/- 6 sqrt(2)

x = 6 +/- 6 sqrt(2)

Answer 3

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