Algebra investment question

Question

Sarah has $2000 more invested at 8.5% than she does at 9.75%. Both investments are at simple interest rates. If the annual return from each investment is the same, how much is invested at each rate?

Answer 1

.085(x) = .0975(x-2000)

.085x = .0975x - 195

.0125x = 195

x/80 = 195

x = 80(195) = 15600

x = 195/.0125 = $15,600 invested at 8.5%

x-2000 = $13,600 invested at 9.75%

.085(15600) = .0975(13,600)

1326 = 1326