
Yefim S. answered 05/25/21
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im (n→∞) n ∑ i=1 [(2xi+3)/n] = ∫04(2x + 3)/4dx = (x2 + 3x)/404 = 7
Dianz S.
asked 05/25/21The interval [0,4] is partitioned into n equal subintervals, and a number xi is arbitrarily chosen in the i^th subinterval for each i. Then:
lim (n→∞) n ∑ i=1 [(2xi+3)/n] = ?
Yefim S. answered 05/25/21
Math Tutor with Experience
im (n→∞) n ∑ i=1 [(2xi+3)/n] = ∫04(2x + 3)/4dx = (x2 + 3x)/404 = 7
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