Three capacitors of values of 1.0 μF, 1.5 μF, and 2.0 μF each are connected in series. What is the equivalent capacitance?

Answer 1

Equivalent Capacitance for three capacitors in series can be given by the following equation.

1/C = 1/C1 + 1/C2 + 1/C3

Substitute the values from the problem into this equation to find the answer.

1/C = 1/1 + 1/2 + 1/1.5

1/C = 3/2 + 2/3

1/C = 13/6

C= 6/13 (or approximately .46153) micro farads