Woojin L.
asked 05/20/21
An astronaut travels at 0.93c. As one hour passes for her how much time passes for an observer on earth?
Answer: 2.72 hours = 2 hours and 43 minutes
Method:
Lorentz equation for time dilation is t'=γt, which means the time as measured in the frame of the astronaut (t) multiplied by the Lorentz Factor (γ is the letter gamma but it looks like garbo using wyzants greek letters) is equal to the time as measured by an observer
Lorentz Factor γ = 1/(√(1-(v/c)^2))
Calculation
γ = 1/(√(1-(.93)^2)) = 2.72
t'= 2.72 • 1hr = 2.72 hrs
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