Physics (forces)

Question

A net force of 10.5 N [E] acts on a 25 kg bike. If the final velocity of the bike is 8.0 m/s [E] after 5.0 s, what was the initial velocity of the bike?

Answer 1

The net force of 10.5 N acting on a mass of 25 kg results in an acceleration of 10.5 / 25 kg = 0.42 m/s².

Acceleration is the change in velocity divided by the time or A = (V_final - V_initial) / t.

Solve for V_initial and substitute for A, V_final and t.

V_initial = 8.0 m/s - 0.42m/s² x 5 s = 5.9 m/s