Find sin θ and tan θ, given that cos θ = 3/5 and sin θ < 0

Question

Find sin θ and tan θ, given that cos θ = 3/5 and sin θ < 0

sin0=?

tan0=?

Answer 1

cosx = 3/5 = adjacent side over hypotenuse = a/h

opposite side squared = h^2 -a^2 = 25-9 = 16

the opposite side, o, = -4, since sinx<0

the angle is in quadrant IV

sinx = o/h =-4/5

tanx = o/a =-4/3

(x is theta)