A spring has a force constant of 520.50 N/m. What is the elastic potential energy stored in the spring when it is stretched 0.45 m from equilibrium?

Answer 1

The equation for the potential energy stored in a spring is PE = 1/2 * k * x² where k is the force constant and x is the displacement from the equilibrium position.

PE = 1/2 * 520.50 N/m * 0.45² m² = 53 joules to 2 sig. figs.