Light traveling in air with the index of refraction n1 of 1.000, is incident on a material with an index of refraction n2 of 1.55. Calculate the Brewster’s angle

Answer 1

Brewster's angle is the angle of incidence at which the electric field component of the incident light parallel to the plane of incidence is not reflected; consequently, the reflected ray is polarized in a plane perpendicular to the plane of incidence.

The formula giving Brewster's angle is θ = arctan n_t / n_i where n_t is the index of refraction of the transmission medium and n_i is the index of refraction of the incident medium.

In the present case the angle is arctan 1.55/1.00 = 57.2°.