T= 0.6 sin(pi\/28 x - 8) + 101.4, What is the temp when t=2?

Answer 1

T = .6(sin[(pi/28)x] -8) + 101.4

for x= 2

T = .6(sin(pi/14) - 8) + 101.4

T =.6(sin(180/14) - 8) + 101.4

T =about .6(.22-8) + 101.4

= .6(-1.78) + 101.4

= - 1.07 + 101.4 = 100.33 = temperature when x=2