A block of aluminum weighing 140.0 grams is cooled from 98.4C to 62.2C with the release of 4428J of heat. Calculate the specific heat of aluminum.

Question

Use q=mcAt to solve this physics problem.

Answer 1

With q = mcΔT, 4428 J = (140.0 g) c (98.4 - 62.2 °C) = 5068 c, then c = 0.874 J/g °C (only 3 sig figs in ΔT).