Daniel B. answered 05/17/21
A retired computer professional to teach math, physics
The function arcsec is normally defined to have the range [0,π], where the derivative is always positive.
Therefore
d/du(arcsec(u)) = 1/(|u|√(u²-1))
To calculate your derivative of h(x), use the substitution u = x/3.
That makes
du/dx = 1/3
dh/dx =
d/dx(6×arcsec(x/3)) =
6×d/dx(arcsec(x/3)) =
6×d/du(arcsec(u))×du/dx =
6×(1/(|u|√(u²-1)))×(1/3) =
2/(|u|√(u²-1)) =
2/(|x/3|√(x²/9 - 1)) =
18/(|x|√(x² - 9))