7. What the frequency of the photon emitted when an electron goes from the 4th energy level (E4 = -0.85eV) to the 3rd energy level (E3 = -1.51eV) b. 2.05 x1014hz c. 3.65 x1014hz d. 5.70 x1014hz

Question

a. 1.59 x 1014hz

show calculations! thank you

Answer 1

Energy difference ΔE = 0.66 ev * (1.602 x 10^-19 J / 1 ev) = 1.057 x 10^-19 J = h•f, f = (1.057 x 10^-19 J) / (6.626 x 10^-34 Js) = 1.6 x 10¹⁴ Hz = answer a.