Natalie P.
asked 05/07/21Create a equation for both.
A population of rabbits oscillates 19 above and below an average of 94 during the year, hitting the lowest value in January (t = 0). Find an equation for the population, P, in terms of the months since January, t.
1 Expert Answer
Daniel B. answered 05/07/21
A retired computer professional to teach math, physics
Let
A = 19 be the amplitude of oscillation
m = 94 be the average
T = 12 be the period
The general form is
P(t) = m + A sin(2πt/T + φ)
The only thing remaining is to determine the phase φ so that
minimum occurs at t = 0, while minimum for sin(x) occurs at x = -π/2.
Therefore φ = -π/2
The final result is
P(t) = 94 + 19 sin(2πt/12 - π/2)
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Natalie P.
What if the lowest value of the rabbit population occurred in April instead?06/15/21