Remember the Trig Identity 1 + tan2(x) = sec2(x)
We can subtract 1 from both sides to get tan2(x) = sec2(x) - 1
Therefore,
8cot2(y)(sec2(y) − 1) =
8cot2(y)tan2(y) [using the substitution above]
Note that cot2(y) = 1 / tan2(y)
Therefore,
8cot2(y)tan2(y) = 8(1) = 8