sin2x = 1 - cos2x
Using sin x < 0, sin x = -√(1 - cos2x) = -√48 / 7 = -4√3/7
cotx = cos(x) / sin(x) = (1/7) / (-4√3/7) = -1/4√3 = -√3 /12
Sael P.
asked 05/02/21Find cot x if cos x= 1/7 and sin x <0
sin2x = 1 - cos2x
Using sin x < 0, sin x = -√(1 - cos2x) = -√48 / 7 = -4√3/7
cotx = cos(x) / sin(x) = (1/7) / (-4√3/7) = -1/4√3 = -√3 /12
Mark M. answered 05/02/21
Mathematics Teacher - NCLB Highly Qualified
sin2 + cos2 = 1
Then select the negative value for sine.
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