The partial fraction decomposition of 20/(x-1)(x+1) can be written in the form of f(x)/x-1 +g(x)/x+1,where f(x)= g(x)=

Question

The partial fraction decomposition of 20/(x-1)(x+1) can be written in the form of f(x)/x-1 +g(x)/x+1,where

f(x)=

g(x)=

Answer 1

20/[(x-1)(x=1)] = A/(x-1) + B/(x+1)

So, 20 = A(x+1) + B(x-1)

0x + 20 = (A+B)x + (A-B)

A+B = 0 and A-B = 20

So, A = 10 and B = -10

Partial Fraction Decomposition: 20/[(x-1)(x+1)] = 10/(x-1) - 10/(x+1)