Bradford T. answered 05/01/21
Retired Engineer / Upper level math instructor
a) y = mx+b
6 = m+b
30 = 2m+b
subtracting the 1st from the 2nd equation
24 = m
6 = 24+b
b = -18
f(x) = 24x-18
b) y = ax2+b
6 = a+b
30 = 4a+b
24 = 3a
a = 8
6=8 + b
b = -2
f(x) = 8x2-2
c) y = aebx
6 = aeb
30 = ae2b
ln(6) = ln(a) + b
ln(30) = ln(a) + 2b
b = ln(30) - ln(6) = ln(5)
ln(a) = ln(6) - ln(5)
ln(a) = ln(6/5)
a = 6/5
y = (6/5)eln(5)x
= (6/5)5x
f(x) = 6(5)x-1