A light ray in airstrikes an air-water interface at an angle of incidence of 50°. What happens? What is the angle of refraction?

Answer 1

Use Snell's law n₁ sin θ₁ = n₂ sin θ₂, with n₁ = 1.00 for air and n₂ = 1.33 for water: 1.00 sin 50° = 1.33 sin θ₂ which yields sin θ₂ = 0.7660/1.33 and θ₂ = 35.2°. The ray refracts towards the normal line.