Jordan B.

asked • 04/27/21

(Find all solutions of the equation in the interval [0, 2𝜋). 2 sin(4x) = −4 sin(2x)

Mahmoud M.

sin(2x)=2sin(x)cos(x) than sin(4x)=2sin(2x) cos(2x) than the equation will be 2(2sin(2x)cos(2x))=-4sin(2x) (divide by 4) sin(2x)cos(2x)+sin(2x)=0 sin(2x)[ cos(2x)+1]=0 so sin2x=0 or cos(2x)=- 1 x=0 or 2x=180 , x=90
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04/27/21

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