Inactive Tutor answered 03/14/13
Using some log laws:
log3(27x)2 = 2(log3(27x)) = 2(log327 + log3x) = 2(log333 + log3x) = ...
Gfffffffffffffffff F.
asked 03/13/13xbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbb
Inactive Tutor answered 03/14/13
Using some log laws:
log3(27x)2 = 2(log3(27x)) = 2(log327 + log3x) = 2(log333 + log3x) = ...
Inactive Tutor answered 03/13/13
Do you want to simplify it?
Assume 3 is the base. Then you have
Log3(27x)^2 = 2log3 (27|x|) = 2[3 + log3 |x|], since log3 27 = 3
Attn: You need to add absolute sign for x.
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