An aluminum wing on a passenger jet is 36 m long when its temperature is 22°C. At what temperature would the wing be 7 cm (0.07 m) shorter?

Answer 1

Change in length / Original length = Temp Coefficient * Fall in temperature

0.07/36 = Temp Coefficient * fall in temp

Fall in Temp = 1.944*10 ^-3 / Temp Coefficient

2.2*10 ^-5 = Temp Coefficient of expansion of Al

Fall in temp == 88⁰C final temp = 20-88 = - 66⁰C