
Julien S. answered 04/23/21
University Student Mathematics Major Experienced in Tutoring
sin(x) never goes past 1, so that's immediately off the table. Just by looking at ln(x), we can already conclude that it's way slower than x^20 and 2^x. Comparing x^20 and 2^x, it might seem that x^20 is faster, and it is at the beginning, but at infinity, 2^x grows way faster. The easiest way to see this is to compare the growth rates. The derivative of x^20 is 20x^19, and 2^x is ln2(2^x). Comparing the growth rates of the growth rates, at some point of taking derivatives, the one coming from x^20 will become a constant, while the one coming from 2^x will still have an x. Working backwards shows us that, after a while, the growth rate increases faster for 2^x, which means 2^x grows faster as x approaches infinity. This is pretty much what L'Hopital's rule is.
This is kind of hard to visualize, but you can try playing around with it on a calculator. You'll see that at some point, 2^x starts to overtake x^20.
Sreeram K.
Correct! Thanks alot04/23/21