A 0.300 kg mass is attached to a 26.6 N/m spring. It is pulled 0.120 m and released. How much Potential Energy does it have when it is 0.0600 m from equilibrium?

Answer 1

The elastic potential energy equation is EPE = (1/2) k x², where k is the spring constant and x the distance from equilibrium. EPE = (0.5)*(26.6 N/m)*(0.0600 m)² = 0.0479 Joules.