This is not separable, but we can use an integration factor (in this case sin(x)) which we will multiply both sides by to make the left-hand side of the diff eq the recognizable derivative of a product of functions:
Multiply by sin(x):
sin(x)·dy/dx +cos(x)·y = 5exsin(x)
d[sin(x)·y]/dx = 5exsin(x). We integrate both sides now; the right-hand side is integrable using int by pts:
sin(x)·y = [-5excos(x) +exsin(x)] / 2 + C
y = [-5excot(x) + ex] / 2 + C / sin(x)
Ahmed Q.
wolud you plz solv this eq (𝑦′′ − 2𝑥𝑦′ + 2𝑦 = 0 ; 𝑦1 = 𝑥)04/22/21