Mark M. answered 04/20/21
Retired math prof. Very extensive Precalculus tutoring experience.
sinC / 38 = sin28°/27
27sinC = 38sin28°
sinC = 0.6607
∠C = Sin-1(0.6607) or 180° - Sin-1(0.6607) = 41.4° or 138.6°
If ∠C = 41.4°, then ∠A = 180° - 28° - 41.4° = 110.6°
So, sin110.6° / a = sin28°/27. Therefore, a = 53.8
If ∠C = 138.6°, then ∠A = 180° - 138.6° - 28° = 13.4°
So, sin13.4° / a = sin28° / 27 Therefore, a = 13.3
First Triangle: a = 53.8, b = 27, c = 38, ∠A = 110.6°, ∠B = 28°, ∠C = 41.4°
Second Triangle: a = 13.3, b = 27, c = 38, ∠A = 13.4°, ∠B = 28°, ∠C = 138.6°