You're correct that the answer is B!
Since you're right, I'll go relatively quickly through my explanation just to show the correct steps you'd take to solve this problem:
Separate dM/dt = -kM as such:
(1/M) × dM = -k dt
Integrating both sides, we get:
ln(M) = -kt + C
∴ M = e -kt + C
We can write it as M = e-kt × eC. Let's call eC = c1
M = c1e-kt. We know that the initial mass is 100 g: At t = 0, M = 100!
100 = c1e-k(0)
100 = c1
∴ Our particular solution is M = 100e-kt, answer b!
