dM / dt = -k M Multiply both sides by dt and divide both sides by M, so
dM = -k M dt
dM /M = -k dt Now get integral from both sides:
Ln M = -k t + C1 So:
M = e^(-kt+C1) this is the same as M = e^(-kt) x e ^ C1. Lets assume e^ C1 is C, so
M = C e^ (-kt) Now plug t = 0 and M = 200, so:
200 = C x 1 meaning C = 200 so the equation will b,
M = 200 e ^ (-kt) which is the forth choice.
Sreeram K.
Correct! Thank you so much!04/20/21